25b^2+10b-48=0

Solution for 25b^2+10b-48=0 equation:

Simplifying
25b2 + 10b + -48 = 0

Reorder the terms:
-48 + 10b + 25b2 = 0

Solving
-48 + 10b + 25b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(-8 + -5b)(6 + -5b) = 0

Subproblem 1
Set the factor '(-8 + -5b)' equal to zero and attempt to solve:

Simplifying
-8 + -5b = 0

Solving
-8 + -5b = 0

Move all terms containing b to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 8 + -5b = 0 + 8

Combine like terms: -8 + 8 = 0
0 + -5b = 0 + 8
-5b = 0 + 8

Combine like terms: 0 + 8 = 8
-5b = 8

Divide each side by '-5'.
b = -1.6

Simplifying
b = -1.6
Subproblem 2
Set the factor '(6 + -5b)' equal to zero and attempt to solve:

Simplifying
6 + -5b = 0

Solving
6 + -5b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + -5b = 0 + -6

Combine like terms: 6 + -6 = 0
0 + -5b = 0 + -6
-5b = 0 + -6

Combine like terms: 0 + -6 = -6
-5b = -6

Divide each side by '-5'.
b = 1.2

Simplifying
b = 1.2
Solution
b = {-1.6, 1.2}